If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7x^2+13x-60=0
a = 7; b = 13; c = -60;
Δ = b2-4ac
Δ = 132-4·7·(-60)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-43}{2*7}=\frac{-56}{14} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+43}{2*7}=\frac{30}{14} =2+1/7 $
| 5x+9x=8 | | 16(p+1)=16 | | 4h+6=3 | | 7d+4d-5d-5d=20 | | 7/3y=1 | | 7(4x+5)=-161 | | 11u-11u+4u=20 | | 35/10=14/x | | 34=y−120 | | -3|a-1|=-15 | | 4(-8-x)=-80 | | 2(c+8)=16 | | 3x+-x=5x-19 | | -x^2+4x-7=2x^2+9x-5 | | 10k-4k-3k+k-3k=10 | | 10+4x=2x+8 | | 18s+11=11 | | X+4=2(x-13) | | 6r^2+102r+432=0 | | x^-18x+74=-6 | | -7x+5+x=-31 | | x/x^2+3x-9=1 | | y/4–2=2 | | -2z+3=-9 | | 2(3+x)=x+7 | | x÷4+10=16 | | 5(2^x+4)=15 | | b-0.17b=83b | | -4+x+3x=-4 | | 18x+6x=180 | | 4(-4z+3)=-1 | | 5a-5a+2a-a=14 |